1Z0-805 무료 덤프문제 온라인 액세스
| 시험코드: | 1Z0-805 |
| 시험이름: | Upgrade to Java SE 7 Programmer |
| 인증사: | Oracle |
| 무료 덤프 문항수: | 90 |
| 업로드 날짜: | 2026-08-20 |
Given the code fragment: public class Test {
public static void main (String [] args) {
Path path1 = Paths.get("D:\\sys\\asm\\.\\data\\..\\..\\mfg\\production.log");
System.out.println(path1.normalize());
System.out.println(path1.getNameCount());
}
}
What is the result?
The two methods of course rescue that aggregate the features located in multiple classes are __________.