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200-301-KR
Cisco.200-301-KR.v2026-06-09.q577 모의시험 (Page 97)

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200-301-KR 문제 476

전시물을 참조하십시오.

R1의 LAN 인터페이스에서 IPv6 주소를 자동으로 할당받아야 합니다. 이 작업을 수행하기 위해 어떤 명령어를 실행해야 합니까?

A. IPv6 주소 2001:dbB:d8d2:1008:4343:61:0010::/64

B. IPv6 주소 자동 구성

C. IPv6 주소 fe80::/10

D. IPv6 주소 DHCP

정답: B

Ipv6 address autoconfig. IP services questions require matching the protocol or service to its exact role in monitoring, addressing, traffic treatment, or application access. Cisco CCNA 200-301 v1.1 includes this under Network Fundamentals, where the expected skill is selecting the feature that actually produces the requested network behavior. The wording normally gives the clue: protocol family, address scope, trunk state, route preference, security mode, API method, or controller role. The wrong choices name real services but solve a different operational problem. In production, choosing the wrong option would typically cause failed client access, a broken route, insecure management, or an automation workflow that targets the wrong interface. The selected answer is the Cisco-consistent behavior for this item.

코멘트: *

성함: *

메일: *

확인코드: *

insert code

200-301-KR 문제 477

전시물을 참조하십시오.

현재 네트워크에서 DR(재해 복구) 서버는 R5이고, BDR(배포 가능 재해 복구) 서버는 R4입니다. 두 서버의 인터페이스가 불안정하게 작동하고 있어 네트워크 엔지니어는 OSPF 네트워크에서 다른 DR과 BDR을 선출하도록 하려고 합니다. 엔지니어가 구현해야 하는 구성은 무엇일까요?

A.

B.

C.

D.

정답: D

The correct response is D. OSPF DR and BDR election on a broadcast network is influenced by interface priority. To force different routers to win, the flapping routers should be given priority 0 or lower priority while the desired routers have higher priority, followed by a neighbor reset if needed. For Cisco CCNA 200-
301 v1.1, the important point is the mechanism, not a generic description of the technology. Changing unrelated process values or router IDs alone does not reliably replace an already elected DR/BDR on a live segment. When this appears in a network, the symptom normally confirms the answer: the route installed, the state selected, the packet forwarded, the wireless client behaviour, or the management workflow will follow this rule. That is why this answer is the best fit for the scenario and not just a plausible networking term.

코멘트: *

성함: *

메일: *

확인코드: *

insert code

200-301-KR 문제 478

조직은 직원 스마트폰의 인증 앱을 사용하여 다단계 인증으로 네트워크를 보호합니다. 사용자의 스마트폰을 분실하거나 도난당한 경우 애플리케이션은 어떻게 보호되나요?

A. 구성된 간격 후에 애플리케이션을 다시 활성화하려면 관리자 비밀번호가 필요합니다.

B. 애플리케이션은 두 번째 요소를 제공하기 전에 사용자에게 PIN을 입력하도록 요구합니다.

C. 애플리케이션은 스마트폰이 재부팅될 때 다시 활성화하기 위해 관리자 비밀번호를 요구하여 사용자에게 요청합니다.

D. 애플리케이션은 두 번째 요소를 제공하기 전에 사용자가 특정 위치에 있는지 확인합니다.

정답: B

The application requires the user to enter a PIN before it provides the second factor.. Security fundamentals require distinguishing identity, authorization, accounting, encryption, inspection, and physical protection.
Cisco CCNA 200-301 v1.1 includes this under Security Fundamentals, where the exam expects engineers to recognize the device behavior that actually produces the required outcome. The question is best solved by reading the operational clue rather than choosing a familiar acronym. The incorrect choices apply a security term in the wrong control category or protect a different part of the system. In a production network, the wrong choice would normally create an outage, leave a management or security gap, or send troubleshooting toward the wrong subsystem. The selected answer is the one that matches the control-plane, data-plane, wireless, security, services, or automation mechanism described in the question. That is why it remains the verified answer for this item.

코멘트: *

성함: *

메일: *

확인코드: *

insert code

200-301-KR 문제 479

PC 주소가 10.1.1.1인 경우 공용 라우팅 가능 주소에 대한 정적 NAT 바인딩을 생성하는 명령은 무엇입니까?
209.165.200.225가 PC에 할당되었습니까?

A. R1(config)#ip nat inside source static 10.1.1.1 209.165.200.225

B. R1(config)#ip nat inside source static 209.165.200.225 10.1.1.1

C. R1(config)#ip nat outside source static 10.1.1.1 209.165.200.225

D. R1(config)#ip nat outside source static 209.165.200.225 10.1.1.1

정답: A

R1(config)#ip nat inside source static 10.1.1.1 209.165.200.225. Cisco routing logic is deterministic: a router first matches the most specific destination prefix, then uses administrative distance when competing route sources advertise the same prefix, and finally evaluates the protocol metric when multiple paths remain inside the same routing protocol. First-hop redundancy protocols add a separate default-gateway resiliency function for hosts on a LAN. The other choices in this question either point to the wrong route-selection rule, confuse a protocol metric with administrative distance, or apply a Layer 2 concept where a Layer 3 forwarding decision is required. In production, that mistake would create blackholing, asymmetric routing, or a backup path that never activates. Cisco CCNA 200-301 v1.1 tests this because route selection is fundamental to troubleshooting reachability. The selected answer matches the behavior Cisco routers use when forwarding traffic or maintaining gateway redundancy.

코멘트: *

성함: *

메일: *

확인코드: *

insert code

200-301-KR 문제 480

전시물을 참조하십시오.

주어진 JSON으로 인코딩된 데이터에는 총 몇 개의 객체가 있습니까?

A. 하나

B. 넷

C. 일곱

D. 9

정답: B

four. Automation questions depend on recognizing controllers, APIs, data formats, HTTP methods, and cloud- service characteristics. Cisco CCNA 200-301 v1.1 includes this under Automation and Programmability, where the expected skill is identifying the mechanism that actually satisfies the scenario. The wording usually gives the decisive clue: a protocol number, a route prefix, a control-plane role, a wireless security method, or a management command. The wrong options mix controller functions with data-plane forwarding or confuse API operations with unrelated management terms. In a real network, selecting the wrong option would usually produce a failed adjacency, broken client connectivity, insecure management access, or an incorrect forwarding path. The selected answer matches the Cisco behavior and configuration model required by the question, so it is retained as the verified answer for this item.

코멘트: *

성함: *

메일: *

확인코드: *

insert code

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